Question 65

A car driver, driving in a fog, passes a pedestrian who was walking at the rate of 2 km/h in the same direction. The pedestrian could see the car for 6 min and it was visible to him up to a distance of 0.6 km. What was the speed of the car?

Solution

Relative speed formula in same direction

S1 and S2 be the speeds of car and passenger respectively and L be the distance travelled.

S1-S2=(L1+L2)/T

So in the question s1=2km/hr

L1+L2=0.6km

T=6min so to covert in hour

6min=1/10hr

So put all the values in the formula

S1-2=(0.6)*10

S1=8km/hr

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