Question 64

The length of a rectangle is three- fifth of the radius of a circle. The radius of the circle is equal to the side of a square whose area is 6400 $$m^{2}$$. The area (in $$m^{2}$$) of rectangle, if the breadth is 20 m is:

Solution

Given,

Area of square = 6400 $$m^{2}$$ (given)

We know,

Area of square = $$\left(side\right)^2$$

$$\therefore\ side\ =\ \ \ \sqrt{\ 6400}=80\ m$$

Side of square = radius of circle (given)

radius = 80 cm

Now, Length of rectangle = three-fifth of radius of circle

l = $$\frac{3}{5}\times\ 80=48\ m$$

b = 20 m (given)

Area of rectangle = $$l\times\ b$$

= $$48\times\ 20=960\ m^2$$

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