The average weight of 38 students is 42 kg. It was found later that the figure of 46 kg was misread as 26 kg in one of the readings. What is the correct average? (correct to one decimal places)
given the average weight of 38 students is 42 kg
$$\frac{\left(sum\ of\ weights\right)}{38}$$ =42
sum of weights=1596
it was found that 46 is misread as 26
so we should add the value of 46-26=20 to the sum and find the average
$$\frac{\left(1596+20\right)}{38}$$
=>42.5
hence answer is option A
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