Let $$\langle a_n \rangle$$ be a sequence such that $$a_1 + a_2 + \ldots + a_n = \frac{n^2 + 3n}{(n+1)(n+2)}$$. If $$28 \sum_{k=1}^{10} \frac{1}{a_k} = p_1 p_2 p_3 \ldots p_m$$, where $$p_1, p_2, \ldots p_m$$ are the first $$m$$ prime numbers, then $$m$$ is equal to

A

$$5$$

B

$$8$$

C

$$6$$

D

$$7$$