470 liters of a mixture of milk and water contains 5% of water. A mischievous boy added some water in the mixture and now there is 6% water in the new mixture. Find the quantity of water added by the boy in the mixture.

470 liters of a mixture of milk and water contains 5% of water.

initial quantity of water = 470 of 5%

= $$470\times\frac{5}{100}$$

= 23.5

initial quantity of milk = 470-23.5

= 446.5

A mischievous boy added some water in the mixture and now there is 6% water in the new mixture.

Let's assume the quantity of water added by the boy in the mixture is 'y' liters.

$$\frac{446.5}{23.5+y}\ =\ \frac{\left(100-6\right)}{6}$$

$$\frac{446.5}{23.5+y}\ =\ \frac{94}{6}$$

$$\frac{9.5}{23.5+y}\ =\ \frac{1}{3}$$

$$28.5\ =\ 23.5+y$$

y = 5 liters