The value of $$\frac{0.2\div0.2of0.1-0.03\div0.6of0.01}{0.25\times0.75\div1.25of0.4+0.125}$$ lies between:
Expression :Â $$\frac{0.2\div0.2of0.1-0.03\div0.6of0.01}{0.25\times0.75\div1.25of0.4+0.125}$$
=Â $$\frac{(0.2\div0.02)-(0.03\div0.006)}{(0.25\times0.75\div0.5)+0.125}$$
= $$\frac{10-5}{0.375+0.125}=\frac{5}{0.5}=10$$
Thus, it lies between 9.5 and 10.5
=> Ans - (C)
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