Question 63

The least number of square tiles of side 41 cms required to pave the ceiling of a room of size 15m 17cm long and 9m 2 cm broad is:

Solution

Length of ceiling = 15m 17 cm = 1517 cm and breadth = 902 cm

Side of square tile = 41 cm

Thus, required number of tiles = $$\frac{1517 \times 902}{41^2}$$

= $$37 \times 22=814$$

=> Ans - (D)

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