Pair of species among the following having same bond order as well as paramagnetic character will be-

Molecular Orbital Theory (MOT) Analysis:

• For $$\text{O}_2^+$$ (15 electrons):
  • Bond Order = $$\frac{10 - 5}{2} = 2.5$$
  • Contains 1 unpaired electron in its antibonding orbitals $$\implies$$ Paramagnetic.
• For $$\text{N}_2^-$$ (15 electrons):
  • Bond Order = $$\frac{10 - 5}{2} = 2.5$$
  • Contains 1 unpaired electron in its antibonding orbitals $$\implies$$ Paramagnetic.

Conclusion:

Both $$\text{O}_2^+$$ and $$\text{N}_2^-$$ are isoelectronic species containing 15 electrons, resulting in an identical bond order of 2.5 and paramagnetic behavior.

Answer: Option B — $$\text{O}_2^+, \text{N}_2^-$$