Question 63

If the probability that A will live 15 years is $$\left(\frac{7}{8}\right)$$ and that B will live 15 years is $$\left(\frac{9}{10}\right)$$, then what is the probability that both will live after 15 years?

Solution

Both the events are independent so if two events are independent say A and B then probability of both happening = P(A) $$\times$$ P(B)

P(A will live 15 more years) = $$\frac{7}{8}$$

P(B will live 15 more years) = $$\frac{9}{10}$$

P(A will live 15 more years and B will live 15 more years) = $$\frac{7}{8}\times\frac{9}{10}$$

= $$\frac{63}{80}$$

=> Ans - (B)

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