Question 63

If A = $$\frac{(0.1)^3 + (0.2)^3 + (0.3)^3 + 3(0.005 + 0.016 + 0.027) + 0.036}{(0.1)^2 + (0.2)^2 + (0.3)^2 + 0.04 + 0.06 + 0.12}$$, then the value of 60A is:

Solution

A = $$\frac{(0.1)^3+(0.2)^3+(0.3)^3+3(0.005+0.016+0.027)+0.036}{(0.1)^2+(0.2)^2+(0.3)^2+0.04+0.06+0.12}$$

$$=\frac{0.001+0.008+0.027+3(0.048)+0.036}{0.01+0.04+0.09+0.22}$$

$$=\frac{0.036+0.144+0.036}{0.01+0.04+0.09+0.22}$$

$$=\frac{0.216}{0.36}$$

$$=\frac{216}{360}$$

$$=$$> 60A = $$60\times\frac{216}{360}=36$$

Hence, the correct answer is Option A

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