A certain sum invested on compound interest grows to ₹8,000 and ₹27,000 in three and six years, respectively when the interest is compounded annually. What is the percentage rate of interest?
A = $$P\left(1+\frac{r}{100}\right)^n$$
27000 = $$P\left(1+\frac{r}{100}\right)^6$$ ----------------I
8000 = $$P\left(1+\frac{r}{100}\right)^3$$ ------------II
Dividing I by II we get,
$$\frac{27}{8}=P\left(1+\frac{r}{100}\right)^3$$
$$\frac{3}{2}=1+\frac{r}{100}$$
$$\frac{r}{100}=\frac{1}{2}$$
$$r=50 %$$
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