Two cars travel from city A to city B at a speed of 36 and 48 km/hr respectively. If one car takes 3 hours lesser time than the other car for the journey, then the distance between City A and City B is

Let the distance between City A and City B = $$d$$ km

Speed of first car = 36 km/hr and speed of second car = 48 km/hr

Let time taken by first car = $$t$$ hrs and time taken by second car = $$(t - 3)$$ hrs

Using, speed = distance/time for first car :

=> $$\frac{d}{t} = 36$$

=> $$d = 36t$$ --------------(i)

For second car, => $$\frac{d}{t - 3} = 48$$

Substituting value of $$d$$ from equation (i), we get :

=> $$36t = 48t - 144$$

=> $$48t - 36t = 12t = 144$$

=> $$t = \frac{144}{12} = 12$$ hrs

From equation (i), => $$d = 36 \times 12 = 432$$ km

=> Ans - (B)