In a 56 liters mixture of milk and water, the ratio of milk to water is 5 : 2. In order to make the ratio of milk to water 7 : 2, some quantity of milk is to be added to the mixture. The quantity of the milk present in the new mixture will be:
Given,
Ratio of milk and water in a 56 liters of mixture = 5 : 2
$$=$$>Â Quantity of milk in 56 liters mixture =Â $$\frac{5}{5+2}\times56=40$$
$$=$$>Â Quantity of water in 56 liters mixture = $$\frac{2}{5+2}\times56=16$$
Let the quantity of milk added to make the mixture in the ratio 7 : 2 = $$a$$
$$=$$> Â $$\frac{40+a}{16}=\frac{7}{2}$$
$$=$$> Â $$40+a=56$$
$$=$$> Â $$a=16$$
$$\therefore\ $$Quantity of milk present in new mixture = 40+a = 40+16 = 56 liters
Hence, the correct answer is Option D
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