If the sum of the square of the roots of the equation $$x^2 - (\sin\alpha - 2)x - (1 + \sin\alpha) = 0$$ is least, then $$\alpha$$ is equal to

A

$$\dfrac{\pi}{6}$$

B

$$\dfrac{\pi}{4}$$

C

$$\dfrac{\pi}{3}$$

D

$$\dfrac{\pi}{2}$$