If sinθ + cosθ = 1, then the sinθ cosθ is equal to
Given : $$sin\theta+cos\theta=1$$
Squaring both sides,
=> $$(sin\theta+cos\theta)^2=1$$
=> $$sin^2\theta+cos^2\theta+2sin\theta cos\theta=1$$
Using, $$(sin^2\theta+cos^2\theta=1)$$
=> $$1+2sin\theta cos\theta=1$$
=> $$2sin\theta cos\theta=1-1=0$$
=> $$sin\theta cos\theta=0$$
=> Ans - (A)
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