Question 62

$$A = 7 \times 21 \div 49 - 8 \times 7 \div 16$$ and $$B = 12 \div 6 - 3 \times 2 + 5 \times 3$$. What is the value of (A $$\times$$ B)

Solution

$$A = 7 \times 21 \div 49 - 8 \times 7 \div 16$$

$$A=7\times\frac{21}{49}-8\times\frac{7}{16}$$

$$A=\frac{21}{7}-\frac{7}{2}$$

A = 3-3.5

A = -0.5

$$B = 12 \div 6 - 3 \times 2 + 5 \times 3$$

$$B = 2-6+15$$

B = 11

Value of (A $$\times$$ B) = $$-0.5\times11$$

= -5.5


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