Question 62

0.5 moles of gas $$A$$ and $$x$$ moles of gas $$B$$ exert a pressure of $$200\text{ Pa}$$ in a container of volume $$10\text{ m}^3$$ at $$1000\text{ K}$$. Given $$R$$ is the gas constant in $$\text{J K}^{-1}\text{ mol}^{-1}$$, $$x$$ is

Solution

Using $$PV = (n_A + n_B)RT$$, $$200 \times 10 = (0.5 + x) \times R \times 1000$$, so $$0.5 + x = \frac{2}{R}$$. Hence $$x = \frac{2}{R} - \frac{1}{2} = \frac{4 - R}{2R}$$.

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