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Chlorine on reaction with hot and concentrated sodium hydroxide gives
With hot, concentrated alkali chlorine disproportionates as $$3\text{Cl}_2 + 6\text{NaOH} \rightarrow 5\text{NaCl} + \text{NaClO}_3 + 3\text{H}_2\text{O}$$. The products are chloride $$\text{Cl}^-$$ and chlorate $$\text{ClO}_3^-$$ (cold dilute alkali gives $$\text{ClO}^-$$ instead).
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