Question 61

If $$\frac{3 \times 7 + 12}{12 \times 7 + 3 \times 4 - 2} =\frac{1}{K}$$, then what is the value of K?

Solution

$$\frac{3 \times 7 + 12}{12 \times 7 + 3 \times 4 - 2} =\frac{1}{K}$$

$$\frac{21+12}{84+12-2}=\frac{1}{K}$$

$$\frac{33}{84+10}=\frac{1}{K}$$

$$\frac{33}{94}=\frac{1}{K}$$

$$K=\frac{94}{33}$$

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