Question 60
When 32% of a number X was added to another number y , then y increases by 24%. The value of $$\frac{(2x+y)}{3x-y}$$ is:
Solution
Given that 0.32x+y=1.24y
0.32x=0.24y
x/y =3/4
Required value=$$\frac{(2x+y)}{3x-y}$$
Substituting x=3 and y=4
=(2(3)+4)/(3(3)-4)
=10/5
=2
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