The correct match between Item I and Item II is:

In Item I the three organic compounds are:

 $$\text{(A) Phenol, } \quad \text{(B) Aniline, } \quad \text{(C) Benzoic acid}$$

Item II lists four characteristic qualitative tests:

 $$\text{(P) Brisk effervescence with } NaHCO_3$$  (carboxylic ‑COOH group)
 $$\text{(Q) Violet colour with } FeCl_3$$  (phenolic -OH group)
 $$\text{(R) White ppt. of } 2,4,6\text{-tribromophenol on } Br_2/H_2O$$  (highly activated phenolic ring)
 $$\text{(S) Foul-smelling isothiocyanate in the carbylamine test}$$  (primary aromatic amine (-NH2))

We now match each compound from Item I with the test(s) it answers in Item II.

Case 1: Phenol (A)
Phenol possesses a phenolic -OH group and an activated aromatic ring.
• The -OH group gives a violet colour with neutral $$FeCl_3$$ solution  ⇒  (Q).
• The ring is activated enough to form a white precipitate of $$2,4,6$$-tribromophenol with aqueous bromine  ⇒  (R).
So $$\text{(A)} \rightarrow (\text{Q, R})$$. Case 2: Aniline (B)
Aniline is a primary aromatic amine. In the carbylamine test (chloroform + alc. KOH) it forms foul-smelling phenyl isothiocyanate.
Thus $$\text{(B)} \rightarrow (\text{S})$$ and it does not respond to the other three tests. Case 3: Benzoic acid (C)
Benzoic acid contains the carboxylic -COOH group which liberates $$CO_2$$ with $$NaHCO_3$$ giving brisk effervescence.
Hence $$\text{(C)} \rightarrow (\text{P})$$ only.

Collecting all the matches:

 $$\boxed{\text{(A) → (Q, R); (B) → (S); (C) → (P)}}$$

This corresponds to Option A.

Therefore, the correct answer is:
Option A which is: (A) → (Q,R); (B) → (S); (C) → (P)