Question 60
The base of right prism is a trapezium whose parallel sides are 11 cm and 15 cm and the distance between them is 9 cm. If the volume of the prism is 1731.6 cm$$^3$$, then the height(in cm) of the prism will be:
Solution
Volume = area of base $$\times height $$
Base area = $$\frac{1}{2} \times (l_1 +Â l_2) \times h$$ =Â $$\frac{1}{2} \times (11 +15) \times 9$$ = 117 cm$$^2$$
Height =Â $$\frac{volume}{base area}$$ =Â $$\frac{1731.6}{117}$$ = 14.8 cm
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