If $$A = \frac{2}{3} \div \frac{4}{9}, B = \frac{6}{11} \times \frac{33}{12}$$ and $$C = \frac{1}{3} \times \frac{9}{2}$$, then what is the value of A $$\times$$ B - C?
$$A = \frac{2}{3} \div \frac{4}{9}$$
$$A=\frac{2}{3}\times\frac{9}{4}$$
$$A=\frac{3}{2}$$
A = 1.5
$$B = \frac{6}{11} \times \frac{33}{12}$$
$$B=\frac{3}{2}$$
B = 1.5$$C = \frac{1}{3} \times \frac{9}{2}$$
$$C=\frac{3}{2}$$
C = 1.5value of A $$\times$$ B - C =Â $$1.5\times1.5-1.5$$
= 2.25-1.5
= 0.75
=Â $$\frac{75}{100}$$
=Â $$\frac{3}{4}$$
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