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Find the iso-electric point of the given amino acid:
For an acidic amino acid (like glutamic acid), the isoelectric point ($$pI$$) is calculated by taking the average of the two lowest $$\mathrm{p}K_a$$ values:
$$pI=\frac{pK_{a1}+pK_{aR}}{2}$$
Substituting the given values:
$$pI=\frac{2+4}{2}$$
$$pI=\frac{6}{2}=3$$
Correct option: (C)
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