Question 60

A hall is 18 m long and 12 m broad. If the area of the floor is equal to the sum of the areas of the four walls, the volume (in $$m^{3}$$ ) of the hall is:

Solution

As shown in the figure,

L = length of the room = 18m

B = width of the room = 12m

H= height of the room

Given,

Area of floor = Area of four walls

$$L\times\ B=2\left(L+B\right)\times\ H$$

$$18\times12=2\left(18+12\right)\times\ H$$

$$\therefore\ H=\frac{18}{5}$$

Volume of cuboid = $$L\times\ B\times\ H$$

= $$18\times12\times\frac{18}{5}$$

= 777.6 $$m^3$$

Hence, Option B is correct.

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