A hall is 18 m long and 12 m broad. If the area of the floor is equal to the sum of the areas of the four walls, the volume (in $$m^{3}$$ ) of the hall is:
As shown in the figure,
L = length of the room = 18m
B = width of the room = 12mÂ
H= height of the room
Given,Â
Area of floor = Area of four walls
$$L\times\ B=2\left(L+B\right)\times\ H$$
$$18\times12=2\left(18+12\right)\times\ H$$
$$\therefore\ H=\frac{18}{5}$$
Volume of cuboid =Â $$L\times\ B\times\ H$$
=Â $$18\times12\times\frac{18}{5}$$
= 777.6Â $$m^3$$
Hence, Option B is correct.Â
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