A 360 m longtrain running at a uniform speed, crosses a platform in 55 seconds and a man standing on the platform in 24 seconds. What is the length (in metre) of the platform?
The train with length 360 m passes by a man standing at the platform in 24 seconds .The speed of the train isÂ
V= 360/24= 15 m/s
Let the length of the platform be L
(L+ 360)/ 55 = 15
L+360= 15*55
L+360=825
L= 825-360
L= 465 m.
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