Please enter the following details
Free Daily Targets & Mocks
Study Material & Formulas PDFs
1 on 1 Mentorship
Question 6
The sum of the cubes of two numbers is 128, while the sum of the reciprocals of their cubes is 2.
What is the product of the squares of the numbers?
Solution
Considering the two numbers to a, b :
We were given that :
$$a^3+b^3\ =\ 128$$
$$\frac{1}{a^3}+\ \frac{1}{b^3}=\ 2$$
$$\frac{\left(a^3+b^3\right)}{a^3\cdot b^3}=\ 2\ =\ \frac{128}{k}$$
k = 64.
Hence $$a^3\cdot b^3\ =\ 64$$
a*b = 4 and $$a^2\cdot b^2\ =\ 16$$
Video Solution
Your Doubts
Ask a Doubt
(know more)
Drop Your File Here!
Ask Your Doubt
Drop Your File Here!
XAT Quant Questions | XAT Quantitative Ability
XAT Inequalities QuestionsXAT Averages, Ratio and Proportion QuestionsXAT Profit and Loss QuestionsXAT Linear Equations QuestionsXAT Probability, Combinatorics Questions
XAT DILR Questions | LRDI Questions For XAT
XAT DI with connected data sets QuestionsXAT Data Interpretation QuestionsXAT Special Charts QuestionsXAT Scheduling QuestionsXAT Data Interpretation Basics Questions
