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Question 6

The $$P-V$$ diagram of a diatomic ideal gas system going under cyclic process as shown in figure. The work done during an adiabatic process $$CD$$ is (use $$\gamma = 1.4$$):

Solution

$$W_{C \rightarrow D} = \frac{P_C V_C - P_D V_D}{\gamma - 1}$$

$$W_{C \rightarrow D} = \frac{100 \times 4 - 200 \times 3}{1.4 - 1} = \frac{400 - 600}{0.4} = \frac{-200}{0.4} = -500\text{ J}$$

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