Question 6
A carpenter can repair $$4$$ tables in $$5$$ hours. The time (in hours) for him to repair, (at the same rate) $$7$$ tables is
Solution
The time required for one table is $$\frac{5}{4}$$ hours. Therefore, the time for $$7$$ tables is $$7 \times \frac{5}{4}=\frac{35}{4}=8\frac{3}{4}$$ hours.
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