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Question 6

A carpenter can repair $$4$$ tables in $$5$$ hours. The time (in hours) for him to repair, (at the same rate) $$7$$ tables is

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The time required for one table is $$\dfrac{5}{4}$$ hours. Therefore, the time for $$7$$ tables is $$7 \times \dfrac{5}{4}=\dfrac{35}{4}=8\dfrac{3}{4}$$ hours.

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