Solution
Let the number be $$x$$ and $$(45 - x)$$
=> Product = $$x (45 - x) = 500$$
=> $$x^2 - 45x + 500 = 0$$
=> $$(x - 25) (x - 20) = 0$$
=> $$x = 25 , 20$$
Other number = $$20 , 25$$
Thus, the two numbers are = 20 and 25
$$\therefore$$ H.C.F. of 20 and 25 = 5
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