Question 58

The areas of three consecutive faces of a cuboid are $$12cm^{2} , 20cm^{2} and 15cm^{2}$$ , then the volume $$(in cm^{3} )$$ of the cuboid is

Solution

Let the length, breadth and height of cuboid be $$l , b , h$$ respectively

Area of three consecutive faces :

=> $$l b = 12$$

$$b h = 20$$

$$h l = 15$$

Multiplying the above equations,

=> $$(lbh)^2 = 12 \times 20 \times 15 = 3600$$

=> $$(lbh) = \sqrt{3600} = 60$$

$$\therefore$$ Volume of cuboid = $$60 cm^3$$

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