If a cone of radius 3.5 cm and height 9.6 cm is melted and constructed into a cylinder of the same radius, what will be the height of this cylinder? (Take π = 22/7)
Let height of cylinder = $$h$$ cm and radius, r = 3.5 cm
Height of cone, H = 9.6 cm and Radius, R = 3.5 cm
Volume of cylinder = Volume of cone
=> $$\pi r^2 h = \frac{1}{3} \pi R^2 H$$
=> $$(3.5)^2 \times h = \frac{1}{3} \times (3.5)^2 \times 9.6$$
=> $$h = \frac{9.6}{3} = 3.2$$ cm
=> Ans - (A)
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