A series is given, with one number missing. Choose the correct alternative from the given ones that will complete the series.
1, 0.125, 1/27, 1/64, ? , 1/216
The series is of the form $$'\frac{1}{n^3}'$$
$$\frac{1}{1^3}$$ = 1
$$\frac{1}{2^3}$$ =Â $$\frac{1}{8}$$ = 0.125
$$\frac{1}{3^3}$$ =Â $$\frac{1}{27}$$
$$\frac{1}{4^3}$$ =Â $$\frac{1}{64}$$
$$\frac{1}{5^3}$$ =Â $$\frac{1}{125}$$ =Â 0.008
$$\frac{1}{6^3}$$ =Â $$\frac{1}{216}$$
=> Ans - (D)
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