Two places P and Q are 162 km apart. A train leaves P for Q and simultaneously another train leaves Q for P. They meet at the end of 6 hours. If the former train travels 8km/hour faster then the other, then speed of train from Qis
Let the speed of the train from Q be X km/hr
Then the speed of the train from P is ( X+8 ) km/hr
They meet each other at M after 6 hours travel
PM + MQ = 162 km
6 ( X + 8 ) + 6X = 162 km
12X + 48 = 162
12X = 162 - 48
12X = 114
X = 114/12
9 (1/2) km/hr
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