The length of each equalside ofan isosceles triangle is 15 cm and the included angle between those twosidesis 90°.Find the area ofthe triangle.
Area of a triangle = $$\frac{1}{2} \times a \times b \times sin\theta $$
a = b = 15 cm
$$\theta = 90\degree$$
Area of a triangle = $$\frac{1}{2} \times 15 \times 15 \times sin90\degree = \frac{225}{2} cm^2$$
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