Question 58

The length of each equalside ofan isosceles triangle is 15 cm and the included angle between those twosidesis 90°.Find the area ofthe triangle.

Solution

Area of a triangle = $$\frac{1}{2} \times a \times b \times sin\theta $$

a = b = 15 cm

$$\theta = 90\degree$$

Area of a triangle = $$\frac{1}{2} \times 15 \times 15 \times sin90\degree = \frac{225}{2} cm^2$$


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App