If the straight lines $$\frac{x - 1}{2} = \frac{y + 1}{k} = \frac{z}{2}$$ and $$\frac{x + 1}{5} = \frac{y + 1}{2} = \frac{z}{k}$$ are coplanar, then the plane(s) containing these two lines is(are)

A

$$y + 2z = -1$$

B

$$y + z = -1$$

C

$$y - z = -1$$

D

$$y - 2z = -1$$