Question 58
If I travel by bus, I reach my office 15 min late, and if I travel by car, I reach 10 min early. If the distance between my home and my office is 25 km, then the difference of the reciprocals of average speeds of the bus and the car, in second per metre is:
Solution
Speed by bus = $$\frac{25000}{900}=\frac{250}{9}\ \frac{m}{s}$$ (Since 1 km = 1000m and 1 min = 60s)
Speed by car = $$\frac{25000}{600}=\frac{250}{6}\ \frac{m}{s}$$
Average speed = $$\frac{2xy}{x+y}$$
2xy = $$2\times\ \frac{250}{9}\times\ \frac{250}{6}$$
x+y=$$\frac{250}{9}+\frac{250}{6}=\frac{1250}{18}$$
$$\frac{2xy}{x+y}$$ = $$\frac{100}{3}\ \frac{m}{s}$$
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
