Question 58

A train 108 m long moving at a speed of 50 km/hr crosses a train 112 m long coming from the opposite direction in 6 seconds. The speed of the second train is

Solution

Sum of lengths of both trains = $$108+112=220$$ m

Speed of first train = 50 km/hr and let speed of second train = $$x$$ km/hr

=> Relative speeds of both trains (in m/s) = $$(50+x)\times\frac{5}{18}$$

Using, Speed = $$\frac{5}{18}(50+x)=\frac{220}{6}$$

=> $$50+x=\frac{220}{6}\times\frac{18}{5}$$

=> $$50+x=132$$

=> $$x=132-50=82$$

$$\therefore$$ Speed of second train = 82 km/hr

=> Ans - (D)

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