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Question 58
A certain sum is divided among A, B and C in such a way that A gets Rs. 40 more than the 1/2 of the sum. B gets Rs. 120 less than 3/8th of the sum and C gets Rs. 200. What is the total sum?
Solution
Let the total sum be Rs. 'x'
Share of A = Rs. $$\frac{x}{2} + 40$$
Share of B = Rs. $$\frac{3x}{8} - 120$$
Share of C = Rs. 200
$$x = \frac{x}{2} + 40 + \frac{3x}{8} - 120 + 200$$
$$x = 960$$
The required sum = RS. 960
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