Total number of compounds with Chiral carbon atoms from following is

 $$CH_3-CH_2-CHNO_2-COOH$$

$$CH_3-CH(I)-CH_2-NO_2$$

$$CH_3-CH_2-CHBr-CH_2-CH_3$$

$$CH_3-CH_2-CH(OH)-CH_2OH$$

Key Concept: A chiral carbon atom (or asymmetric carbon) is a tetrahedral carbon atom ($$sp^3$$ hybridized) that is directly bonded to four entirely different atoms or groups of atoms.

Structure 1: Another molecule shown in the image top part (not completely spelled in text, let's analyze the given four textual lines and the structure image). Let's analyze the explicitly listed compounds sequentially:

Compound 1: $$CH_3-CH_2-CH(NO_2)-COOH$$ (2-Nitrobutanoic acid). Let's examine the carbon atoms in this chain. Carbon-2 is bonded to a methyl/ethyl-derived group ($$-CH_2-CH_3$$), a nitro group ($$-NO_2$$), a carboxylic acid group ($$-COOH$$), and a hydrogen atom ($$-H$$). Since all four groups attached to Carbon-2 are distinct, this carbon is a chiral center. This compound contains a chiral carbon.

Compound 2: $$CH_3-CH(I)-CH_2-NO_2$$ (2-Iodo-1-nitropropane). Let's look closely at Carbon-2. It is directly attached to a methyl group ($$-CH_3$$), an iodine atom ($$-I$$), a nitromethyl group ($$-CH_2-NO_2$$), and a hydrogen atom ($$-H$$). Because all four attached groups are different, Carbon-2 acts as a chiral center. This compound contains a chiral carbon.

Compound 3: $$CH_3-CH_2-CHBr-CH_2-CH_3$$ (3-Bromopentane). Let's examine Carbon-3, which holds the bromine atom. It is bonded to a bromine atom ($$-Br$$), a hydrogen atom ($$-H$$), and two identical ethyl groups ($$-CH_2-CH_3$$ on both sides). Because it does not have four different groups attached, it is achiral. This compound does not contain a chiral carbon.

Compound 4: $$CH_3-CH_2-CH(OH)-CH_2OH$$ (Butane-1,2-diol). Let's look closely at Carbon-2. It is bonded to an ethyl group ($$-CH_2-CH_3$$), a hydroxyl group ($$-OH$$), a hydroxymethyl group ($$-CH_2OH$$), and a hydrogen atom ($$-H$$). Since all four groups are different, Carbon-2 is a chiral center. This compound contains a chiral carbon.

Compound 5: The structure shown in the structural diagram image ($$H_3C-C(H)(I)-CH(I)-C_2H_5$$ or similar polyhalogenated alkane variant). Looking at the molecular graphic representation provided at the bottom: The left highlighted carbon is bonded to $$H_3C-$$, $$-H$$, $$-I$$, and the remaining bulky haloalkyl chain. Thus, it forms a chiral center. The adjacent carbon containing an iodine atom is bonded to $$-I$$, $$-H$$, an ethyl group ($$-C_2H_5$$), and the left haloalkyl portion. This also forms a second chiral center. This compound contains chiral carbons.

Counting the total number of compounds from the problem set that possess a chiral carbon center gives a total of 5 compounds.

Answer: 5