Given, Â $$\cot \theta = \frac{80}{39}$$
$$\therefore\ $$ $$\operatorname{cosec}\theta=\sqrt{1+\cot^2\theta\ }$$
$$=\sqrt{1+\left(\frac{80}{39}\right)^2}$$
$$=\sqrt{1+\frac{6400}{1521}}$$
$$=\sqrt{\frac{1521+6400}{1521}}$$
$$=\sqrt{\frac{7921}{1521}}$$
$$=\frac{89}{39}$$
Hence, the correct answer is Option A
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