If $$A = 7 \times 3 \div (2 + 4) + 4 - 2, B = 3 \div 6 \times 4 + 2 - 2  of  3$$ and $$C = 6 \div 2 + 4 \times 3 - 2$$. What is the value of $$(A + B - C)$$?

A =$$ 7 \times 3 \div (2 + 4) + 4 - 2 $$

  = $$ 7 \times 3 \div 6 + 4 - 2 $$

  = $$ 7 \times \frac{1}{2} + 4 - 2 $$

  = $$ \frac{7}{2} + 2 $$

  = $$ \frac{11}{2} $$

B = $$ 3 \div 6 \times 4 + 2 - 2 of 3 $$

   = $$ 3 \div 6 \times 4 + 2 - 6 $$ 

   = $$ \frac{1}{2} \times 4 + 2 - 6 $$

   = -2

C =$$ 6 \div 2 + 4 \times 3 - 2 $$ 

   = $$ 3 + 4 \times 3 - 2 $$

   = $$ 3 + 12 - 2 $$

   =  13

$$ (A + B - C) = \frac{11}{2} - 2 - 13 = \frac{-19}{2} $$