$$[\frac{SinA}{(1+CosA)}]+[\frac{(1+CosA)}{SinA}]$$ is equal to
Expression : $$[\frac{SinA}{(1+CosA)}]+[\frac{(1+CosA)}{SinA}]$$
Taking L.C.M, we get :
= $$\frac{(sin^2 A) + (1 + cos A)^2}{sin A(1 + cos A)}$$
= $$\frac{sin^2 A + cos^2 A + 2cos A + 1}{sin A(1 + cos A)}$$
Using $$(sin^2 A + cos^2 A = 1)$$
= $$\frac{2 + 2cos A}{sin A(1 + cos A)} = \frac{2(1 + cos A)}{sin A(1 + cos A)}$$
= $$\frac{2}{sin A} = 2 cosec A$$
Create a FREE account and get:
