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If $$x = \sqrt{2} + \sqrt[3]{5}$$ and $$y$$ is such that $$xy$$ is rational, then a value of $$y$$ is
$$(\sqrt[3]{5} - \sqrt{2})(4 + 2\sqrt[3]{25} + 5\sqrt[3]{5})$$
$$(\sqrt[3]{5} - \sqrt{2})$$
$$(\sqrt[3]{5} - \sqrt{2})(2\sqrt[3]{25} + 5\sqrt[3]{5} - 4)$$
$$(\sqrt[3]{5} - \sqrt{2})(4 - 2\sqrt[3]{25} + 5\sqrt[3]{5})$$
If x is rational number then 1/x is also a rational number.
A is correct choice.
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