Question 55

The smallest of the differences between the perfect sqares lying on either side of the least positive integer that is divisible by 3, 4, 5, 6, 8 is

Solution

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LCM(3,4,5,6,8)=120.

So, Smallest number that is divisible by 3,4,5,6,8 is 120.

Now, Smallest square numbers ,which are present on both side of 121, that can produce smallest difference are 100$$\left(10^2\right)$$ and 121$$\left(11^2\right)$$.

So, Smallest difference is (121-100)=21.

D is correct choice.

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