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Question 55
The smallest of the differences between the perfect sqares lying on either side of the least positive integer that is divisible by 3, 4, 5, 6, 8 is
Solution
LCM(3,4,5,6,8)=120.
So, Smallest number that is divisible by 3,4,5,6,8 is 120.
Now, Smallest square numbers ,which are present on both side of 121, that can produce smallest difference are 100$$\left(10^2\right)$$ and 121$$\left(11^2\right)$$.
So, Smallest difference is (121-100)=21.
D is correct choice.
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