AP Police SI Mains 2019 Arithmetic and Reasoning

Question 55

The smallest of the differences between the perfect sqares lying on either side of the least positive integer that is divisible by 3, 4, 5, 6, 8 is

Solution

LCM(3,4,5,6,8)=120.

So, Smallest number that is divisible by 3,4,5,6,8 is 120.

Now, Smallest square numbers ,which are present on both side of 121, that can produce smallest difference are 100$$\left(10^2\right)$$ and 121$$\left(11^2\right)$$.

So, Smallest difference is (121-100)=21.

D is correct choice.


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