Solution
$$2^{x-1} + 2^{x+1}= 160$$
$$\frac{2^x}{2}+2^x\times\ 2=160$$
$$2^x\left(\frac{1}{2}+2\right)=160$$
$$2^x\left(\frac{5}{2}\right)=160$$
$$2^x=64=2^6$$
This gives x = 6.
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