A person loses 75% of his money in the first bet, 75% of the remaining in the second and 75% of the remaining in the third bet and returns home with Rs. 2 only. His initial money was
Let initial money with the person = Rs. $$x$$
The person loses 75% = $$(\frac{3}{4})^{th}$$ of the money in 3 bets, that is after each of the bet, money left with him is 25% =Â $$(\frac{1}{4})^{th}$$
=> Money left after 3 bets = $$(\frac{1}{4})^3 \times x=2$$
=> $$\frac{x}{64}=2$$
=> $$x=2 \times 64=Rs.$$ $$128$$
=> Ans - (B)
Create a FREE account and get:
Day-wise Structured & Planned Preparation Guide
By proceeding you agree to create your account
Free CAT Schedule PDF will be sent to your email address soon !!!
