The average of a set of ten numbers is 40. If a number is removed from the set, then the average of the remaining numbers becomes 38. What was the number that was removed?
The average of a set of ten numbers is 40.
Sum of a set of ten numbers = $$40\times10$$ = 400  Eq.(i)
If a number is removed from the set, then the average of the remaining numbers becomes 38.
New Average after a number is removed from the set = $$38\times9$$ = 342   Eq.(ii)
The number that was removed =Â Eq.(i)- Eq.(ii)
= 400-342
= 58
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