If the nine-digit number 708x6y8z9 is divisible by 99, then whatis the value of x + y + z?
To be divisible by 99, the number has to be divisible by 11 and 9 both.
For divisibility by 11,
7 + 8 + 6 + 8 + 9 - 0 + x + y + z
(38 -Â x + y + z)Â has to be divisible by 11.
For divisibility by 9,Â
(38 + x +Â y + z) has to be divisible by 9.
By option C),
x + y + z = 16
(38 - x + y + z) = 38 - 16 = 22 is divisible by 11.
(38 + x + y + z) = 38 + 16 = 54Â is divisible by 9.
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