Instructions

In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate answer. Give answer

Question 55

I. $$3x^{2} + 10x + 3 = 0$$
II. $$2y^{2} + 15y + 27 = 0$$

Solution

I : 3$$x^{2}$$ + 10x + 3 = 0

=> 3$$x^{2}$$ + 9x + x + 3 = 0

=> 3x ( x + 3) + 1 ( x + 3) = 0

=> (3x + 1) (x + 3) = 0

=> x = -3 , -1/3

II : 2$$y^{2}$$ + 15y + 27 = 0

=> 2$$y^{2}$$ + 6y + 9y + 27 = 0

=> 2y (y+3) + 9 (y + 3) = 0

=> (2y + 9) (y + 3) = 0

=> y = -3 , -9/2

Since, -1/3 > -3 > -9/2

=> x $$\geq$$ y

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I. $$3x^{2} + 10x + 3 = 0$$II. $$2y^{2} + 15y + 27 = 0$$